Centrifugal pump pump shaft power calculation way

what is the efficiency of the pump? The formula?

a: refers to the effective power of the pump and the ratio of the shaft power. Eta = Pe/P < / P > < P > usually refers to the input power of pump power, the power of the prime mover to the pump shaft, so it is also called shaft power, expressed in P.

effective power: water pump lift and the product of the mass flow rate and the acceleration of gravity.

= QH W or Pe = gamma rho g Pe QH / 1000 ( 千瓦)

rho: pump is the density of the fluid ( kg/m3)

gamma: pump liquid severe gamma rho g = ( N / m3)

g: acceleration of gravity, m/s)

mass flow Qm = rho Q t/h or kg/s

a, centrifugal pump shaft power calculation formula

flow * 9 lift. 81 by the proportion of medium present 3600 present pump efficiency

flow units: cubic/hour,

head unit: m

p = 2. 73 hq/eta,

which H as the head, unit m, Q for flow, unit for the m3 / H, eta for the pump efficiency. P for shaft power, the unit KW. Is the pump shaft power P = rho gQH / 1000 eta ( 千瓦) , of which the rho = 1000 kg/m3, g = 9. 8

proportion of the unit is Kg/m3, flow units for the m3 / h, head of the unit is m, 1 Kg = 9. 8 Newton

head traffic proportion p = * * * 9. 8 Newton/Kg

= Kg/m3 * m3 / h * m * 9. 8 Newton/Kg

= 9. Newton * 8 m / 3600 seconds

= Newton * m / 367 seconds

= w / 367

the above derivation is the origin of the unit, the type is the calculation of water power, shaft power divided by efficiency is obtained.

a shaft power for the Ne, motor power of p, K coefficient ( Efficiency of the bottom)

motor power (p = Ne * K K in Ne have different values, see table below)

Ne≤22 K = 1。 25

2, slurry water pump shaft power calculation formula of

flow Q M3 / H

H2O lift H m

efficiency n %

A slurry density KG/M3

shaft power n KW

n Q = H * * * g/A ( n*3600)

the motor power to consider the transmission efficiency and safety coefficient. Take 1 straight league, belt from 0. 96, safety coefficient is 1. 2

3, the pump efficiency and its calculation formula of

refers to the effective power of the pump and the ratio of the shaft power. Eta = Pe/P < / P > < P > usually refers to the input power of pump power, the power of the prime mover to the pump shaft, so it is also called shaft power, expressed in P.

effective power: pump lift and the product of the mass flow rate and the acceleration of gravity.

体育=ρg QH ( W) Or = gamma QH / 1000 (Pe 千瓦)

rho: pump is the density of the fluid ( kg/m3)

gamma: pump liquid severe gamma rho g = ( N / m3)

g: acceleration of gravity, m/s)

mass flow Qm = rho Q ( T/h or kg/s)

4, empirical method to estimate household pump power

family use, the minimum is 370 w, the biggest generally no more than 5. 5 kw, can look for such as a flashlight, or droplight, see its size directly, and then estimates the power size.

5, estimate the power of the well pump

by electric measurement method to calculate, can electrify, find clamp table to measure the current, current multiplied by the power factor is multiplied by the voltage power ( The public number: pump pipe home) , consider the power factor is 0. 8, this can work out the practical work of power, if the water is pumped, can consider to 7 into load design, divided by zero. 8 is the power rating of the machine.

also can turn off the water valve and so on, let the motor idling with pump directly, in this case, the current is not expected to exceed 40% of the rated current, the measured current, calculate the same power, divided by zero. 4 to get the motor power, the comparisons above, to determine whether the motor power is wrong.

can measure pump and ground distance, look at the height of the pumping out, know that head, and then find a bucket, and see it for 1 minute how many pump up the water, measure the volume of water, which in turn to calculate flow rate, know the head and flow rate can, in turn, the computing power. Head * flow present 367. 02÷1. 2, can consider the efficiency of pump is 0. 7, divided by zero. 7, is probably the motor power.

the pump and motor, work in damp environment for a long time, itself might have leakage problem, there may be bias current, and the bearing and line may be there is abnormal, the power can make a big discrepancy, above these methods, the use is only a reference, the actual or comparison is in order to well under processing, after all the equipment should also regularly check.

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