And how to calculate the water pump outlet pressure and lift relationship

head is refers to the energy gained by the unit weight of liquid through the pump, it includes several parts such as potential energy, pressure and speed can, so the outlet pressure is just part of it. But for some cases, the pressure can head in proportion of the percentage of energy is much larger than the other, so it can be used in the engineering practice outlet pressure roughly estimate head, used to determine the pump running situation. Water pump outlet pressure and lift the relationship between the two is: pump lift length depends on the outlet pressure of the pump.

a, pump outlet pressure and head to refer to different

1, the water pump lift: refers to the unit weight energy gained by the fluid through the pump.

2, outlet pressure: refers to the pump outlet pressure table.

2, pump outlet pressure and lift calculation method of different

1, the pump head: the head size depends on the structure of the pump, such as the size of the impeller diameter, blade bending condition, speed, etc. The water pump head can't theoretically make a precise calculation.

2, outlet pressure, is flushing fluid flows through borehole flushing cycle system by all kinds of resistance, therefore, pump pressure is equal to washing fluid flows through the circulatory system throughout the sum of the pressure loss.

3, pump outlet pressure and head loss calculation method of different

1, the pump head, can be determined through experiment, namely in the pump inlet to a vacuum gauge, the exit to a pressure gauge, excluding the two table section on the kinetic energy of the poor ( The Δ u2/2 g = 0) Energy loss, regardless of the two tables of the sections.

2, outlet pressure, the pressure loss including flushing fluid flowing through the core tube and the pressure loss of annular space between the core and flushing fluid flows through bit turning the change direction of pressure loss, and through the tube and the annular space between the pressure loss of hole wall, multi-purpose test method or collect empirical data.

4, pump outlet pressure and lift the conversion formula of

water pump outlet pressure and the head of the conversion formula: H = p/r

H: is equal to the outlet pressure p/r fluid severe

p: pump outlet pressure Pa;

r: fluid severe equal density by g;

rho: the density of water 1000 kg/m3, or pumping fluid density;

g: gravity acceleration

p = rho * g * H ( P - The pressure, unit: = Pa; ; ρ- Density and unit: = kg/m3; g - Gravity and speed, unit: = 10 m/s2. H - Height, in meters)

       P=ρ* g* H*10^ ( - 5) ( P - The pressure, unit: = bar; ; ρ- Density and unit: = kg/m3; g - Acceleration of gravity, the unit: = 10 m/s2. H - Height, in meters)

such as the water pump outlet pressure is 1 kg/cm2 (p Say 1 kg of water pressure in the control engineering) , general condition of the density of water is 1000 kg/m3, are:

H = p/r

= ( 1kg/ cm2) / ( 1000公斤/立方米)

= ( 10000kg/m2) / ( 1000 kg/m3)

= 10 m through the above formula can be concluded that: 1 mpa pressure is equal to about 100 m head, 1 kg of water pressure to zero. 1MPa。 Which is 1 mpa = 100 m = 10 kilograms.

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